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python字符串过滤性能比较5种方法

yipeiwu_com5年前 (2020-03-06)Python基础

python字符串过滤性能比较5种方法比较

总共比较5种方法。直接看代码：

import random
import time
import os
import string

base = string.digits+string.punctuation
total = 100000

def loop(ss):
  """循环"""
  rt = ''
  for c in ss:
    if c in '0123456789':
      rt = rt + c
  return rt

def regular(ss):
  """正则表达式"""
  import re
  rt = re.sub(r'\D', '', ss)
  return rt

def filter_mt(ss):
  """函数式"""
  return filter(lambda c:c.isdigit(), ss)

def list_com(ss):
  """列表生成式"""
  isdigit = {'0': 1, '1': 1, '2': 1, '3': 1, '4': 1,
            '5':1, '6':1, '7':1, '8':1, '9':1}.has_key
  return ''.join([x for x in ss if isdigit(x)])

def str_tran(ss):
  """string.translate()"""
  table = string.maketrans('', '')
  ss = ss.translate(table,string.punctuation)
  return ss

if __name__ == '__main__':
  lst = []
  for i in xrange(total):
    num = random.randrange(10, 50)
    ss = ''
    for j in xrange(num):
      ss = ss + random.choice(base)
    lst.append(ss)

  s1 = time.time()
  map(loop,lst)
  print "loop: ",time.time() - s1
  print '*'*20
  s1 = time.time()
  map(regular, lst)
  print "regular: ", time.time() - s1
  print '*' * 20
  s1 = time.time()
  map(str_tran, lst)
  print "str_tran: ", time.time() - s1
  print '*' * 20
  s1 = time.time()
  map(filter_mt, lst)
  print "filter_mt: ", time.time() - s1
  print '*' * 20
  s1 = time.time()
  map(list_com, lst)
  print "list_com: ", time.time() - s1

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