Python多线程经典问题之乘客做公交车算法实例
本文实例讲述了Python多线程经典问题之乘客做公交车算法。分享给大家供大家参考，具体如下：
问题描述：
乘客乘坐公交车问题，司机，乘客，售票员协同工作,通过多线程模拟三者的工作。
司机：开车，停车
售票员：打开车门，关闭车门
乘客：上车，下车
用Python的Event做线程同步通信，代码如下：
# *-* coding:gb2312 *-*
import threading
import time
stationName=("车站0","车站1","车站2","车站3","车站4","车站5","车站6")
currentStationIndex = -1
eventBusStop = threading.Event()
eventClosedDoor = threading.Event()
eventOpenedDoor = threading.Event()
stationCount = len(stationName)
class Passenger(threading.Thread):
def __init__(self,no,getonStation,getoffStation):
self.no =no
self.getonStation=getonStation
self.getoffStation=getoffStation
threading.Thread.__init__(self)
def run(self):
bExit= False
global currentStationIndex
global stationCount
bAlreadyGetOnStation = False
while not bExit:
eventOpenedDoor.wait()
if self.getonStation == currentStationIndex and bAlreadyGetOnStation == False:
print "乘客%d在%s上车" %(self.no,stationName[currentStationIndex])
bAlreadyGetOnStation =True
elif self.getoffStation == currentStationIndex:
print "乘客%d在%s下车" %(self.no,stationName[currentStationIndex])
bExit = True
time.sleep(1)
class Driver(threading.Thread):
def run(self):
bExit= False
global currentStationIndex
global stationCount
while not bExit:
print "司机: 公交车开始行驶....."
time.sleep(5)
currentStationIndex += 1
print "司机: 到站 ",stationName[currentStationIndex]
eventBusStop.set()
eventClosedDoor.wait()
eventClosedDoor.clear()
if currentStationIndex == stationCount-1:
bExit= True
class Conductor(threading.Thread):
def run(self):
bExit= False
global currentStationIndex
global stationCount
while not bExit:
eventBusStop.wait()
eventBusStop.clear()
print "售票员打开车门：%s到了" %(stationName[currentStationIndex])
eventOpenedDoor.set()
time.sleep(5)
print "售票员关闭车门"
eventOpenedDoor.clear()
eventClosedDoor.set()
if currentStationIndex == stationCount-1:
bExit = True
def test():
passPool=[]
passPool.append(Passenger(0,0,3))
passPool.append(Passenger(1,1,3))
passPool.append(Passenger(2,2,4))
passPool.append(Passenger(3,0,5))
passPool.append(Passenger(4,1,3))
passPool.append(Passenger(5,2,4))
passPool.append(Passenger(6,4,5))
passPool.append(Passenger(7,0,2))
passPool.append(Passenger(8,1,3))
passPool.append(Conductor())
passPool.append(Driver())
leng = len(passPool)
for i in range(leng):
passPool[i].start()
if __name__=='__main__':
test()
输出结果如下：
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希望本文所述对大家Python程序设计有所帮助。
