python实现按首字母分类查找功能
本文实例为大家分享了python实现按首字母分类查找的具体代码，供大家参考，具体内容如下
要求：
1.自己查找一些英文词汇，存储到某个容器类中
2.根据英文词汇的首字母进行分类，类似于手机通讯簿中的快速查找功能
3.根据用户输入的字母，找到该字母开头的所有单词
#coding=utf-8
lexicons=["the","be","of","and","A","to","in","he","have","it","that","for","they","I","with","as","not","on","she","at","by","this","we","you","do","but","from","or","which","one","would","all","will","there","say","who","make","when","can"]
while True:
startLetter=raw_input("输入一个字母，列出所有以此字母开头的单词:")
if len(startLetter)!=1:
print "必须是一个字母"
else:
reLexicons=[] #结果列表
for x in xrange(len(lexicons)):
lexicon=lexicons[x]
if lexicon[0].lower()==startLetter.lower():#都转为小写后比较 开头字母不区分大小写
reLexicons.append(lexicon)
if len(reLexicons)==0:
print "没有结果"
else:
for x in xrange(len(reLexicons)):
print reLexicons[x]
上面的代码没有走第二步，如下代码 使用字典解决第二步
#coding=utf-8
'''
边遍历，边构造 key value
'''
lexicons=["the","be","of","and","A","to","in","he","have","it","that","for","they","I","with","as","not","on","she","at","by","this","we","you","do","but","from","or","which","one","would","all","will","there","say","who","make","when","can"]
lexiconDict={}
#分类 保存字典中
lexiconLen=len(lexicons)
for x in xrange(len(lexicons)):
lexicon=lexicons[x]
startLetter=lexicon[0]
dictLexicons=lexiconDict.get(startLetter,[])
#空列表说明没有Key 则添加Key 否则追加Key对应的Value
if len(dictLexicons)==0:
lexiconDict[startLetter]=[lexicons[x]]
else:
dictLexicons.append(lexicons[x])
while True:
startLetter=raw_input("输入一个字母，列出所有以此字母开头的单词:")
if len(startLetter)!=1:
print "必须是一个字母"
else:
lexicons=lexiconDict.get(startLetter.lower(),[])
if len(lexicons)==0:
print "没有结果"
else:
for x in lexicons:
print x
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持【听图阁-专注于Python设计】。
