num = 905;
def is_Palindrome(num):
  """
  判断一个数字是不是回文数，这里有些取巧了
  :param num:
  :return:
  """
  """
  :param num:
  :return:
  """
  temp = "%d"%num;
  str = temp[::-1];
  if temp == str:
    return True;
  else:
    return False;
def create_Palindrome(num):
  """
  用196算法计算指定数字的回文数
  :param num:
  :return:
  """
  count = 0;
  while True:
    if True == is_Palindrome(num):
      output = "这是一个回文数:%d"%num + "\r\n总共次数为%d"%count;
      print(output);
      break;
    else:
      num = add(num);
      count += 1;
def add(num):
  """
  num 与自己倒序的数字相加
  :param num:
  :return:
  """
  temp = "%d"%num;
  str = temp[::-1];
  return int(temp) + int(str);
print(create_Palindrome(num));