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python爬虫基于requests模块的get请求实现详解

yipeiwu_com7年前 (2020-03-06)Python爬虫

需求：爬取搜狗首页的页面数据

import requests
# 1.指定url
url = 'https://www.sogou.com/'
# 2.发起get请求:get方法会返回请求成功的响应对象
response = requests.get(url=url)
# 3.获取响应中的数据：text属性作用是可以获取响应对象中字符串形式的页面数据
page_data = response.text
# 4.持久化数据
with open("sougou.html","w",encoding="utf-8") as f:
  f.write(page_data)
  f.close()
print("ok")

requests模块如何处理携带参数的get请求，返回携带参数的请求

需求:指定一个词条，获取搜狗搜索结果所对应的页面数据

之前urllib模块处理url上参数有中文的需要处理编码，requests会自动处理url编码

发起带参数的get请求

params可以是传字典或者列表

def get(url, params=None, **kwargs):
  r"""Sends a GET request.
  :param url: URL for the new :class:`Request` object.
  :param params: (optional) Dictionary, list of tuples or bytes to send
    in the body of the :class:`Request`.
  :param \*\*kwargs: Optional arguments that ``request`` takes.
  :return: :class:`Response <Response>` object
  :rtype: requests.Response

import requests
# 指定url
url = 'https://www.sogou.com/web'
# 封装get请求参数
prams = {
  'query':'周杰伦',
  'ie':'utf-8'
}
response = requests.get(url=url,params=prams)
page_text = response.text
with open("周杰伦.html","w",encoding="utf-8") as f:
  f.write(page_text)
  f.close()
print("ok")

利用requests模块自定义请求头信息，并且发起带参数的get请求

get方法有个headers参数把请求头信息的字典赋给headers参数

import requests
# 指定url
url = 'https://www.sogou.com/web'
# 封装get请求参数
prams = {
  'query':'周杰伦',
  'ie':'utf-8'
}
# 自定义请求头信息
headers={
  'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_12_0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36',
  }
response = requests.get(url=url,params=prams,headers=headers)
page_text = response.text
with open("周杰伦.html","w",encoding="utf-8") as f:
  f.write(page_text)
  f.close()
print("ok")

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