python 采用paramiko 远程执行命令及报错解决

yipeiwu_com5年前Python基础

这篇文章主要介绍了python 采用paramiko 远程执行命令及报错解决,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下

import sys
import paramiko
import config_reader
from check_utils import standout_print, parse_remainsize_response_lines, error_out_print
from time import time


class RemoteModel:
  """ remote options model
  execute remote command
  """

  def __init__(self, host, port=22):
    self.hostname = host
    self.port = port

    self.username, self.password = self.load_conf()
    self.s = None
    self.session = None
    self.init_conn()

  def load_conf(self):
    """
      read config get the login info of remote host machine
    :return:
      login username and password of SSH login of this host
    """
    if self.hostname.find("10.179.1.110") != -1:
      error_out_print("Error : the remote machine of KOR can not provide. please know")
      sys.exit(-1)

    username, password = config_reader.read_login_config(self.hostname)

    if not username or not password:
      error_out_print(
        'Error: can not find ssh login info in this host[%s]. check need ' % self.hostname)
      sys.exit(-1)

    return username, password

  def init_conn(self):
    """
      make a connection with the remote machine
    :return:
    """
    try:
      paramiko.util.log_to_file("paramiko_log.log")
      self.s = paramiko.SSHClient()
      self.s.set_missing_host_key_policy(paramiko.AutoAddPolicy())
      self.s.connect(hostname=self.hostname, port=self.port, username=self.username, password=self.password)

      standout_print('success connect the remote machine [host=%s]' % self.hostname)

    except Exception, e:
      standout_print(str(e))
      standout_print(
        'connect failed.in host[%s] user[%s] or pwd[%s] maybe wrong. ' % (
          self.hostname, self.username, self.password))
      sys.exit(-1)

  def close(self):
    """
    close
    if close can not use this connection
    :return:
    """
    if self.s:
      self.s.close()
      self = None

  def execute_command(self, command):
    """
    :param command:
      execute cmd
    :return:
      the response lines
    """
    standout_print("Info: execute command [%s]" % command)
    stdin, stdout, stderr = self.s.exec_command(command)
    stdin.write("pwd"+"\n")
    stdin.flush()

    response_lines = stdout.readlines()
    error_info = stderr.read()

    if error_info and error_info.strip():
      error_out_print(' remote command error info : %s' % stderr.read())
      error_out_print(error_info)
      return None

    # info_arr = response_info.split('\n')

    return response_lines

  def remain_space_size(self, directory_path):
    """
    :param directory_path:

    :return:
      free size of the directory
      unit size : MB
    """

    cmd = 'sudo df -m %s 1>&2' % directory_path # /usr/local/pgsql/data/ssd1

    response_lines = self.execute_command(cmd)
    # response_lines = self.execute_command_channel(cmd)

    return parse_remainsize_response_lines(response_lines)

  def execute(self, command, sudo=False):
    feed_password = False
    if sudo and self.username != "root":
      command = "sudo %s" % command
      feed_password = "pwd"
    stdin, stdout, stderr = self.s.exec_command(command, get_pty=True)
    if feed_password:
      stdin.write(self.password + "\n")
      stdin.flush()
    return {'out': stdout.readlines(),
        'err': stderr.readlines(),
        'retval': stdout.channel.recv_exit_status()}


if __name__ == '__main__':
  host = ""
  hostname = ""
  command = "sudo df -m /data/pgsql94/data"
  rm = RemoteModel(host=hostname)
  print rm.execute_command(command)
  # print rm.execute("df -m /data/pgsql94/data 1>&2", True)

报错1:

remote command error info : 
sudo: sorry, you must have a tty to run sudo

是由于

self.s.exec_command(command, get_pty=True)

没有设置

get_pty=True

报错2:

会卡死在

stdout.readlines()

是由于 SSH在等待输入用户名的密码

stdin.write("pwd"+"\n")
stdin.flush()

该种方式进行交互,注意必须要换行"\n",和前面必须不能有空格等其他字符,确保密码正确

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持【听图阁-专注于Python设计】。

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