python如何获取apk的packagename和activity
这篇文章主要介绍了python如何获取apk的packagename和activity,文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下
实现代码如下：
# 找出packagename和activity
import os
import re
class packagename_activity:
def get_packagename(self, path):
aapt = []
os.system(f'aapt dump badging {path}> ../xc_logs/AaptLog.txt')
with open('../xc_logs/AaptLog.txt', 'rb') as f:
p1 = "package: name='(.+?)'"
results1 = re.finditer(pattern=p1, string=f.readline().decode('utf-8'))
for r in results1:
packagename = r.group(1)
aapt.append(packagename)
p2 = "launchable-activity: name='(.+?)'"
st = str(f.readlines())
results2 = re.findall(p2, st)
activity = results2[0]
aapt.append(activity)
return aapt
if __name__ == '__main__':
a=packagename_activity()
b=a.get_packagename('../xc_apk/wangyiyunyinyue.apk')
print(b)
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持【听图阁-专注于Python设计】。