python使用正则表达式检测密码强度源码分享
复制代码 代码如下:
#encoding=utf-8
#-------------------------------------------------------------------------------
# Name: 模块1
# Purpose:
#
# Author: Administrator
#
# Created: 10-06-2014
# Copyright: (c) Administrator 2014
# Licence: <your licence>
#-------------------------------------------------------------------------------
import re
def checklen(pwd):
return len(pwd)>=8
def checkContainUpper(pwd):
pattern = re.compile('[A-Z]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkContainNum(pwd):
pattern = re.compile('[0-9]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkContainLower(pwd):
pattern = re.compile('[a-z]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkSymbol(pwd):
pattern = re.compile('([^a-z0-9A-Z])+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkPassword(pwd):
#判断密码长度是否合法
lenOK=checklen(pwd)
#判断是否包含大写字母
upperOK=checkContainUpper(pwd)
#判断是否包含小写字母
lowerOK=checkContainLower(pwd)
#判断是否包含数字
numOK=checkContainNum(pwd)
#判断是否包含符号
symbolOK=checkSymbol(pwd)
print(lenOK)
print(upperOK)
print(lowerOK)
print(numOK)
print(symbolOK)
return (lenOK and upperOK and lowerOK and numOK and symbolOK)
def main():
if checkPassword('Helloworld#123'):
print('检测通过')
else:
print('检测未通过')
if __name__ == '__main__':
main()
平时用正则不多，不知道怎么写一个正则满足要求，用了比较笨的办法，谁知道一句正则检验的请赐教!