python静态方法实例

yipeiwu_com5年前Python基础

本文实例讲述了python静态方法。分享给大家供大家参考。

具体实现方法如下:

复制代码 代码如下:
staticmethod Found at: __builtin__
staticmethod(function) -> method
    
    Convert a function to be a static method.
    
    A static method does not receive an implicit first argument.
    To declare a static method, use this idiom:
    
    class C:
    def f(arg1, arg2, ...): ...
    f = staticmethod(f)
    
    It can be called either on the class (e.g. C.f()) or on an
     instance
    (e.g. C().f()).  The instance is ignored except for its class.
    
    Static methods in Python are similar to those found in
     Java or C++.
    For a more advanced concept, see the classmethod builtin.
  
class Employee:
   """Employee class with static method isCrowded"""
 
   numberOfEmployees = 0  # number of Employees created
   maxEmployees = 10  # maximum number of comfortable employees
 
   def isCrowded():
      """Static method returns true if the employees are crowded"""
 
      return Employee.numberOfEmployees > Employee.maxEmployees
 
   # create static method
   isCrowded = staticmethod(isCrowded)
 
   def __init__(self, firstName, lastName):
      """Employee constructor, takes first name and last name"""
 
      self.first = firstName
      self.last = lastName
      Employee.numberOfEmployees += 1
 
   def __del__(self):
      """Employee destructor"""
 
      Employee.numberOfEmployees -= 1    
 
   def __str__(self):
      """String representation of Employee"""
 
      return "%s %s" % (self.first, self.last)
 
# main program
def main():
   answers = [ "No", "Yes" ]  # responses to isCrowded
   
   employeeList = []  # list of objects of class Employee
 
   # call static method using class
   print "Employees are crowded?",
   print answers[ Employee.isCrowded() ]
 
   print "\nCreating 11 objects of class Employee..."
 
   # create 11 objects of class Employee
   for i in range(11):
      employeeList.append(Employee("John", "Doe" + str(i)))
 
      # call static method using object
      print "Employees are crowded?",
      print answers[ employeeList[ i ].isCrowded() ]
 
   print "\nRemoving one employee..."
   del employeeList[ 0 ]
 
   print "Employees are crowded?", answers[ Employee.isCrowded() ]
 
if __name__ == "__main__":
   main()

希望本文所述对大家的Python程序设计有所帮助。

相关文章

介绍一款python类型检查工具pyright(推荐)

介绍一款python类型检查工具pyright(推荐)

近日,微软在 Github 上开源了一个 Python 静态类型检查工具:pyright ,引起了社区内的多方关注。 微软在开源项目上的参与力度是越来越大了,不说收购 Github 这种...

树莓派+摄像头实现对移动物体的检测

树莓派+摄像头实现对移动物体的检测

在上一篇文章中实现了树莓派下对摄像头的调用,有兴趣的可以看一下:python+opencv实现摄像头调用的方法 接下来,我们将使用python+opencv实现对移动物体的检测 一、环境...

使用python分析统计自己微信朋友的信息

首先,你得安装itchat,命令为pip install itchat,其余的较为简单,我不再说明,直接看注释吧。 以下的代码我在Win7+Python3.7里面调试通过 __aut...

python中xrange和range的区别

range 函数说明:range([start,] stop[, step]),根据start与stop指定的范围以及step设定的步长,生成一个序列。range示例:复制代码 代码如下...

Python实现基于POS算法的区块链

Python实现基于POS算法的区块链

区块链中的共识算法 在比特币公链架构解析中,就曾提到过为了实现去中介化的设计,比特币设计了一套共识协议,并通过此协议来保证系统的稳定性和防攻击性。 并且我们知道,截止目前使用最广泛,...