Python3调用微信企业号API发送文本消息代码示例
本文主要向大家分享了Python3调用微信企业号API发送文本消息示例的有关代码，具体如下：
#!/usr/bin/env python
# -*- coding:utf-8 -*-
import urllib.request
import json
import sys
import logging
touser = '@all'
agentid = 0
corpid = 'wx5aef2da956514535'
corpsecret = 'Co17m_OPlvE8Q4P2RKKwtq5oIA3p42xGUZEvCHBI8S0'
url = 'https://qyapi.weixin.qq.com'
subject = sys.argv[2]
message = sys.argv[3]
logging.basicConfig(level=logging.DEBUG, filename='E:\Python_project\Scripts\my.log',
format='%(asctime)s - %(levelname)s: %(message)s')
class Weixin:
def __init__(self, url, corpid, corpsecret):
token_url = '%s/cgi-bin/gettoken?corpid=%s&corpsecret=%s' % (url, corpid, corpsecret)
self.token = json.loads(urllib.request.urlopen(token_url).read().decode())['access_token']
def send_message(self, url, data):
send_url = '%s/cgi-bin/message/send?access_token=%s' % (url, self.token)
self.respone = urllib.request.urlopen(urllib.request.Request(url=send_url, data=data)).read()
x = json.loads(self.respone.decode())['errcode']
if x == 0:
logging.debug('Successfully %s %s' % (subject, message))
return 'Succesfully'
else:
logging.debug('Failed %s %s' % (subject, message))
return 'Failed'
def messages(self, subject, message):
values = {
"touser": touser,
"msgtype": 'text',
"agentid": agentid,
"text": {'content': subject + message},
"safe": 0
}
return self.send_message(url, bytes(json.dumps(values), 'utf-8'))
if __name__ == '__main__':
obj = Weixin(url, corpid, corpsecret)
ret = obj.messages(subject, message)
总结
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