python 删除指定时间间隔之前的文件实例
遍历指定文件夹下的文件，根据文件后缀名，获取指定类型的文件列表；根据文件列表里的文件路径，逐个获取文件属性里的“修改时间”，如果“修改时间”与“系统当前时间”差值大于某个值，则删除该文件。
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Document: Remove Synctoycmd sync expired .tmp files"""
import os
import time
import datetime
def diff():
'''time diff'''
starttime = datetime.datetime.now()
time.sleep(10)
endtime = datetime.datetime.now()
print "time diff: %d" % ((endtime-starttime).seconds)
def fileremove(filename, timedifference):
'''remove file'''
date = datetime.datetime.fromtimestamp(os.path.getmtime(filename))
print date
now = datetime.datetime.now()
print now
print 'seconds difference: %d' % ((now - date).seconds)
if (now - date).seconds > timedifference:
if os.path.exists(filename):
os.remove(filename)
print 'remove file: %s' % filename
else:
print 'no such file: %s' % filename
FILE_DIR = 'D:/'
if __name__ == '__main__':
print 'Script is running...'
#diff()
while True:
ITEMS = os.listdir(FILE_DIR)
NEWLIST = []
for names in ITEMS:
if names.endswith(".txt"):
NEWLIST.append(FILE_DIR + names)
#print NEWLIST
for names in NEWLIST:
print 'current file: %s' % (names)
fileremove(names, 10)
time.sleep(10)
print "never arrive..."
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