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python制作简单五子棋游戏

yipeiwu_com6年前 (2020-03-06)Python基础

本文实例为大家分享了python五子棋游戏的具体代码，供大家参考，具体内容如下

#五子棋
‘''
矩阵做棋盘 16*16 “+”

打印棋盘 for for

游戏是否结束

开始下棋 while 游戏是否结束：
黑白交替 player=0 p%2==0 ==1 p+=1
下棋动作一样但是棋子不一样
‘''

代码

#创建棋盘的程序
def initBoard():
 global board #调用全局的board
 board=[None]*16
 for i in range(len(board)):
 board[i]=["+ "]*16
#打印棋盘的程序
def printBoard():
 global board
 for i in range(len(board)):
 for j in range(len(board[i])):
  print(board[i][j],end=" ")
 print("")
#开始下棋的程序
def startGame():
 global board
 player=0
 while isGameContinue():
 if player%2==0:
  #黑方下棋
  print("==>黑方下棋")
  if not playChess("●"):
  continue
 else:
  #白方下棋
  print("==>白方下棋")
  if not playChess("○"):
  continue
 player+=1

def playChess(chess):
 #获取位置
 x=int(input("==> X="))-1
 y=int(input("==> Y="))-1
 if board[x][y]=="+ ":
 board[x][y]=chess
 printBoard()
 return True #落子成功
 else:
 print("==> 已有棋子 请重新落子\a")
 printBoard()
 return False#落子失败
def isGameContinue():
 for i in range(len(board)):
 for j in range(len(board[i])):
  if board[i][j]!="+ ":
  #横向
  if j<=11:
   if board[i][j]==board[i][j+1]==board[i][j+2]==board[i][j+3]==board[i][j+4]:
   whoWin(i,j)
   return False
  #竖向
  if i<=11:
   if board[i][j]==board[i+1][j]==board[i+2][j]==board[i+3][j]==board[i+4][j]:
   whoWin(i,j)
   return False
  #反斜
  if i<=11 and j<=11:
   if board[i][j]==board[i+1][j+1]==board[i+2][j+2]==board[i+3][j+3]==board[i+4][j+4]:
   whoWin(i,j)
   return False
  #正斜
  if i>=4 and j<=11:
   if board[i][j]==board[i-1][j+1]==board[i-2][j+2]==board[i-3][j+3]==board[i-4][j+4]:
   whoWin(i,j)
   return False
 return True
def whoWin(i,j):
 if board[i][j]=="●":
 print("黑方胜！")
 else:
 print("白方胜！")
 for i in range(10):
 print("\a")
board=[] 
initBoard()
printBoard()
startGame()

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持【听图阁-专注于Python设计】。