python字典序问题实例
本文实例讲述了python字典序问题，分享给大家供大家参考。具体如下：
问题描述:
将字母从左向右的次序与字母表中的次序相同,且每个字符最大出现一次..例如:a,b,ab,bc,xyz等都是升序的字符串.现对字母表A产生的所有长度不超过6的升序字符串按照字典充排列并编码如下:
| 1 | 2 | .. | 26 | 27 | 28 | ... |
| a | b | .. | z | ab | ac | .. |
对一个升序字符串,迅速计算出它在上述字典中的编码。
实现代码如下:
import string
all_letter = string.ascii_lowercase
def gen_dict():
result = {}
list_num_one = [ a_letter for a_letter in all_letter ]
list_num_two = [ i + j for i in all_letter for j in all_letter[all_letter.find(i)+1:]]
list_num_three = [ i + j + k for i in all_letter
for j in all_letter[all_letter.find(i)+1:]
for k in all_letter[all_letter.find(j)+1:]]
list_num_four = [ i + j + k + l for i in all_letter
for j in all_letter[all_letter.find(i)+1:]
for k in all_letter[all_letter.find(j)+1:]
for l in all_letter[all_letter.find(k)+1:]]
list_num_five = [ i + j + k + l + m for i in all_letter
for j in all_letter[all_letter.find(i)+1:]
for k in all_letter[all_letter.find(j)+1:]
for l in all_letter[all_letter.find(k)+1:]
for m in all_letter[all_letter.find(l)+1:]]
list_num_six = [ i + j + k + l + m + n for i in all_letter
for j in all_letter[all_letter.find(i)+1:]
for k in all_letter[all_letter.find(j)+1:]
for l in all_letter[all_letter.find(k)+1:]
for m in all_letter[all_letter.find(l)+1:]
for n in all_letter[all_letter.find(m)+1:]
]
for key,value in enumerate(list_num_one + list_num_two + list_num_three + list_num_four + list_num_five + list_num_six):
result.setdefault(key+1,value)
return result
my_dict = gen_dict()
value_to_get = 'abcdef'
for key,value in my_dict.iteritems():
if value == value_to_get:
print key
结果:83682
即abcdef在字典中的编码。
希望本文所述对大家的Python程序设计有所帮助。