Python实现删除Android工程中的冗余字符串
Android提供了一套很方便的进行资源（语言）国际化机制，为了更好地支持多语言，很多工程的翻译往往会放到类似crowdin这样的平台上。资源是全了，但是还是会有一些问题。
哪些问题
以下使用一些语言进行举例。其中values为工程默认的资源。
1.某语言的资源和某语言限定区域的资源之间。如values-fr-rCA存在于values-fr相同的字符串，这种表现最为严重。
2.某语言的资源和默认的资源之间。values-fr存在与values相同的字符串，可能原因是由于values-fr存在未翻译字符串导致
为什么要去重
洁癖，容不下半点冗余。
解决思路
1.如果values-fr-rCA存在于values-fr相同的字符串，去除values-fr-rCA中的重复字符串，保留values-fr。这样可以保证在values-fr-rCA下也可以正确读取到资源。
2.如果values-fr存在与values相同的字符串。如去除values-fr中得重复字符串，保留values的条目。
Py脚本
#!/usr/bin/env python
# coding=utf-8
from os import listdir,path, system
from sys import argv
try:
import xml.etree.cElementTree as ET
except ImportError:
import xml.etree.ElementTree as ET
def genRegionLangPair(filePath):
basicLanguage = None
if ('values' in filePath) :
hasRegionLimit = ('r' == filePath[-3:-2])
if (hasRegionLimit):
basicLanguage = filePath[0:-4]
if (not path.exists(basicLanguage)) :
return None
belongsToEnglish = ("values-en" in basicLanguage)
if (belongsToEnglish):
#Compare with the res/values/strings.xml
return (path.dirname(basicLanguage) + '/values/strings.xml', filePath + "/strings.xml")
else:
return (basicLanguage + '/strings.xml', filePath + "/strings.xml")
return None
def genLangPair(filePath):
def shouldGenLanPair(filePath):
if (not 'values' in filePath ):
return False
if('dpi' in filePath):
return False
if ('dimes' in filePath):
return False
if ('large' in filePath):
return False
return True
if(shouldGenLanPair(filePath)):
basicLanguage = path.dirname(filePath) + '/values/strings.xml'
targetLanguage = filePath + '/strings.xml'
if (not path.exists(targetLanguage)):
return None
if (not path.samefile(basicLanguage,targetLanguage)) :
return (basicLanguage, targetLanguage)
return None
def genCompareList(filePath):
compareLists = []
for file in listdir(filePath):
regionPair = genRegionLangPair(filePath + '/' + file)
if (None != regionPair):
compareLists.append(regionPair)
languagePair = genLangPair(filePath + '/' + file)
if (None != languagePair) :
compareLists.append(languagePair)
return compareLists
def getXmlEntries(filePath):
root = ET.ElementTree(file=filePath).getroot()
entries = {}
for child in root:
attrib = child.attrib
if (None != attrib) :
entries[attrib.get('name')] = child.text
print 'xmlEntriesCount',len(entries)
return entries
def rewriteRegionFile(sourceEntries, filePath):
if (not path.exists(filePath)):
return
ET.register_namespace('xliff',"urn:oasis:names:tc:xliff:document:1.2")
tree = ET.ElementTree(file=filePath)
root = tree.getroot()
print root
totalCount = 0
removeCount = 0
unRemoveCount = 0
print len(root)
toRemoveList = []
for child in root:
totalCount = totalCount + 1
attrib = child.attrib
if (None == attrib):
continue
childName = attrib.get('name')
if (sourceEntries.get(childName) == child.text):
removeCount = removeCount + 1
toRemoveList.append(child)
else:
unRemoveCount = unRemoveCount + 1
print childName, sourceEntries.get(childName), child.text
print filePath,totalCount, removeCount,unRemoveCount
for aItem in toRemoveList:
root.remove(aItem)
if (len(root) != 0 ):
tree.write(filePath, encoding="UTF-8")
else:
command = 'rm -rf %s'%(path.dirname(filePath))
print command
system(command)
def main(projectDir):
lists = genCompareList(projectDir + "/res/")
for item in lists:
print item
src = item[0]
dest = item[1]
rewriteRegionFile(getXmlEntries(src),dest)
if __name__ == "__main__":
if (len(argv) == 2) :
main(argv[1])
如何使用
python removeRepeatedStrings.py your_android_project_root_dir
