python实现统计代码行数的方法
本文实例讲述了python实现统计代码行数的方法。分享给大家供大家参考。具体实现方法如下:
''' Author: liupengfei Function: count lines of code in a folder iteratively Shell-format: cmd [dir] Attention: default file encode is utf8 and default file type is java-source-file. But users can customize this script by just modifing global variables. ''' import sys import os import codecs from _pyio import open totalCount = 0; fileType = '.java' descLineBegin = '//' descBlockBegin = r'/**' descBlockEnd = r'*/' fileEncode = 'utf-8' def main(): DIR = os.getcwd() if len(sys.argv) >= 2: DIR = sys.argv[1] if os.path.exists(DIR) and os.path.isdir(DIR): print('target directory is %s' % DIR) countDir(DIR) print('total code line is %d' % totalCount) else: print('target should be a directory!') def isFileType(file): return len(fileType) + file.find(fileType) == len(file) def countDir(DIR): for file in os.listdir(DIR): absPath = DIR + os.path.sep + file; if os.path.exists(absPath): if os.path.isdir(absPath): countDir(absPath) elif isFileType(absPath): try: countFile(absPath) except UnicodeDecodeError: print( '''encode of %s is different, which is not supported in this version!''' ) def countFile(file): global totalCount localCount = 0 isInBlockNow = False f = codecs.open(file, 'r', fileEncode); for line in f: if (not isInBlockNow) and line.find(descLineBegin) == 0: pass; elif (not isInBlockNow) and line.find(descBlockBegin) >= 0: if line.find(descBlockBegin) > 0: localCount += 1 isInBlockNow = True; elif isInBlockNow and line.find(descBlockEnd) >= 0: if line.find(descBlockEnd) + len(descBlockEnd) < len(line): localCount += 1 isInBlockNow = False; elif (not isInBlockNow) and len(line.replace('\\s+', '')) > 0: localCount += 1 f.close() totalCount += localCount print('%s : %d' % (file, localCount)) if __name__ == '__main__': main();
希望本文所述对大家的Python程序设计有所帮助。