Python实现通讯录功能
说实话，第一次写这么长的Python代码，期间遇到了很多问题，但是，最终还是完成了，花了我一天半的时间。
该程序实现了用户的增，删，改，查，主要用到sqlite3模块。对于该模块的知识点，请查看我的另一篇文章SQLite-Python
如有更好的建议，请私信，本人将不胜荣幸，让我们一起来学习Python！
#-*- coding:utf-8 -*-
import sqlite3
#打开本地数据库用于存储用户信息
conn = sqlite3.connect('mysql_person.db')
#在该数据库下创建表，创建表的这段代码在第一次执行后需要注释掉，否则再次执行程序会一直提示：该表已存在
conn.execute('''CREATE TABLE MT
(ID INT PRIMARY KEY NOT NULL,
NAME TEXT NOT NULL,
AGE INT NOT NULL,
ADDRESS CHAR(50),
SALARY REAL);''')
print "Table created successfully";
conn.close()
#增加用户信息
def insert():
ID = input('请输入用户ID:\n')
NAME = raw_input('请输入用户昵称:\n')
AGE = input('请输入年龄:\n')
ADDRESS = raw_input('请输入用户地址:\n')
SALARY = input('请输入用户薪水:\n')
sql1 = 'insert into MT(ID,NAME,AGE,ADDRESS,SALARY)'
sql1 += 'values("%d","%s","%d","%s","%d");'%(ID,NAME,AGE,ADDRESS,SALARY)
conn.execute(sql1)
conn.commit()
print "Records insert successfully"
#删除用户信息
def delete():
name = raw_input("请输入所要删除的联系人姓名:")
cursor = conn.execute("SELECT name from MT where name = '%s';"%name)
for row in cursor:
if name == row[0]:
conn.execute("DELETE from MT where name = '%s';"%name)
conn.commit()
print "Records delete successfully"
break
else:
print "sorry,不存在该用户"
#修改用户信息
def modify():
name = raw_input("请输入要修改用户的姓名:")
print search()
sql4 = "SELECT id, name, age,address, salary from MT where name = '%s';"%name
cursor = conn.execute(sql4)
x = raw_input("请输入要修改用户的新地址:")
y = input("请输入要修改用户的新年龄:")
z = input("请输入要修改用户的新薪水:")
sql3 = "UPDATE MT set address = '%s',age = '%d',\
salary = '%d' where name = '%s';"%(x,y,z,name)
conn.execute(sql3)
conn.commit()
print "修改成功"
sql5 = "SELECT id, name, age,address, salary from MT where name = '%s';"%name
cursor = conn.execute(sql5)
for row in cursor:
print "ID = ", row[0]
print "NAME = ", row[1]
print "AGE = ",row[2]
print "ADDRESS = ", row[3]
print "SALARY = ", row[4], "\n"
#查询用户信息
conn = sqlite3.connect('mysql_person.db')
def search():
conn = sqlite3.connect('mysql_person.db')
name = raw_input('请输入要查询的用户姓名')
sql2 = "SELECT id,name,age, address, salary from MT where name= '%s';" % (name)
cursor = conn.execute(sql2)
for row in cursor:
print "ID = ", row[0]
print "NAME = ", row[1]
print "AGE = ",row[2]
print "ADDRESS = ", row[3]
print "SALARY = ", row[4], "\n"
break
else:
print "sorry,没有该用户信息"
#显示所有用户信息
def showall():
cursor = conn.execute("SELECT id, age, name, address, salary from MT")
for row in cursor:
print "ID = ", row[0]
print "NAME = ", row[1]
print "AGE = ",row[2]
print "ADDRESS = ", row[3]
print "SALARY = ", row[4], "\n"
print "Operation done successfully";
cursor = conn.execute("select count(*) from MT;")
for row in cursor:
print "一共有%d个用户"%row[0]
def menu():
print '1.新增联系人'
print '2.删除联系人'
print '3.修改联系人'
print '4.查询联系人'
print '5.显示所有联系人'
print '6.退出程序'
print 'What do you want to do?'
while True:
menu()
x = raw_input('请输入您的选择菜单号:')
if x == '1':
insert()
continue
if x == '2':
delete()
continue
if x == '3':
modify()
continue
if x == '4':
search()
continue
if x == '5':
showall()
continue
if x == '6':
print "谢谢使用！"
exit()
continue
else:
print "输入的选项不存在，请重新输入！"
continue
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持【听图阁-专注于Python设计】。