python实现一组典型数据格式转换
本文实例为大家分享了一组典型数据格式转换的python实现代码，供大家参考，具体内容如下
有一组源数据，第一行会是个日期数据，第二行标明字段，再接下来是两行数据行。
1018 14:31:30.193
Type Succ Fail
sour_sm 1308 1205
data_sm 2205 3301
1019 16:32:30.201
Type Succ Fail
data_sm 3308 2206
data_sm 1765 1105
1020 18:00:00.203
Type Succ Fail
sour_sm 7804 1105
data_sm 2976 1300
要转换成数据
Time Type Succ Fail Total
1018 14:31:30.193 sour_sm 1308 1205 2513
1018 14:31:30.193 data_sm 2205 3301 5506
1019 16:32:30.201 data_sm 3308 2206 5514
1019 16:32:30.201 data_sm 1765 1105 2870
1020 18:00:00.203 sour_sm 7804 1105 8909
1020 18:00:00.203 data_sm 2976 1300 4276
这个时候可以使用Python来处理，代码如下:
# coding = utf-8
fd = open(r"output.txt", "w", encoding="utf-8")
fd.write("%s\t\t\t\t%s\t%s\t%s\t%s\n" % ("Time", "Type", "Succ", "Fail", "Total"))
with open(r"data.txt", "r", encoding="utf-8") as fd1:
lines = fd1.readlines()
time1 = lines[0::4]
data1 = lines[2::4]
data2 = lines[3::4]
for (i, line) in enumerate(time1):
Time = line.strip()
Type_1 = data1[i].strip().split()[0]
Succ_1 = data1[i].strip().split()[1]
Fail_1 = data1[i].strip().split()[2]
Total_1 = str(int(Succ_1) + int(Fail_1))
Type_2 = data2[i].strip().split()[0]
Succ_2 = data2[i].strip().split()[1]
Fail_2 = data2[i].strip().split()[2]
Total_2 = str(int(Succ_2) + int(Fail_2))
fd.write("%s\t%s\t%s\t%s\t%s\n" % (Time, Type_1, Succ_1, Fail_1, Total_1))
fd.write("%s\t%s\t%s\t%s\t%s\n" % (Time, Type_2, Succ_2, Fail_2, Total_2))
fd.close()
生成文件格式如下，基本上满足了需求。
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持【听图阁-专注于Python设计】。