python实现Virginia无密钥解密

yipeiwu_com6年前Python基础

本文实例为大家分享了Virginia无密钥解密的具体代码,供大家参考,具体内容如下

加密

virginia加密是一种多表替换加密方法,通过这种方法,可以有效的解决单表替换中无法应对的字母频度攻击。这种加密方法最重要的就是选取合适的密钥,一旦密钥被公开,保密性也就无从谈起。结合virginia加密原理,给出使用python实现的代码

plainText = "whenigotthethemeithoughtofgooglesartificialintelligencealphagothisprogramoverthebestofhumanplayeriwanttoaskwhenscienceandtechnologycontinuetodevelopwehumanbeingswillbewhatpositionweshouldrealizethatthedevelopmentofscienceandtechnologyisirreversibleanditconstituteaprimaryprductiveforcebutmanmustkeeppacewiththetimestoenhancetheablitytocontrol" # 密文
alphabet = "abcdefghijklmnopqrstuvwxyz" # 26个字母
cipherText = "";
key = "helloworld" # 密钥
keyLen = len(key)
plainTextLen = len(plainText)
j = 0
for i in range(0,plainTextLen):
 j = i%keyLen
 keyNum = alphabet.index(key[j])
 plainNum = alphabet.index(plainText[i])
 plainTemp = alphabet[(keyNum*plainNum)%26] # 密钥对明文作用
 cipherText += plainTemp
print(cipherText)

解密

重点谈谈解密部分。这里的解密主要分为获取密钥长度,根据密钥长度获取密钥,根据密钥获取明文三个部分。

获取密钥长度

使用暴力破解密钥长度的方法,循环遍历可能的密钥长度。每次循环中,记录在这种密钥长度下重复相隔密钥长度密文的次数,从理论上来讲,次数最多的那个密钥长度,最有可能正确。当密文长度足够长时,正确的可能性很高。给出获取密钥长度的python函数代码:

def getKeyLen(cipherText): # 获取密钥长度
 keylength = 1
 maxCount = 0
 for step in range(3,18): # 循环密钥长度
  count = 0
  for i in range(step,len(cipherText)-step):
   if cipherText[i] == cipherText[i+step]: 
     count += 1
  if count>maxCount: # 每次保存最大次数的密钥长度
   maxCount = count 
   keylength = step
 return keylength # 返回密钥长度

获取密钥

当已经获取密钥长度之后,我们可以通过分组将相同密钥作用下的密文进行分组,在每一组中,都是一个简单的单表替换加密。在这种情况下,我们通过重合指数法破解密钥,给出获取密钥部分的python函数代码:

def getKey(text,length): # 获取密钥
 key = [] # 定义空白列表用来存密钥
 alphaRate =[0.08167,0.01492,0.02782,0.04253,0.12705,0.02228,0.02015,0.06094,0.06996,0.00153,0.00772,0.04025,0.02406,0.06749,0.07507,0.01929,0.0009,0.05987,0.06327,0.09056,0.02758,0.00978,0.02360,0.0015,0.01974,0.00074]
 matrix =textToList(text,length)
 for i in range(length):
  w = [row[i] for row in matrix] #获取每组密文
  li = countList(w) 
  powLi = [] #算乘积
  for j in range(26):
   Sum = 0.0
   for k in range(26):
    Sum += alphaRate[k]*li[k]
   powLi.append(Sum)
   li = li[1:]+li[:1]#循环移位
  Abs = 100
  ch = ''
  for j in range(len(powLi)):
    if abs(powLi[j] -0.065546)<Abs: # 找出最接近英文字母重合指数的项
     Abs = abs(powLi[j] -0.065546) # 保存最接近的距离,作为下次比较的基准
     ch = chr(j+97)
  key.append(ch)
 return key 

 破解明文

在已知密钥和明文的基础上,我们很容易就可以得到明文,给出python代码:

def virginiaCrack(cipherText): # 解密函数
 length = getKeyLen(cipherText) #得到密钥长度
 key = getKey(cipherText,length) #找到密钥
 keyStr = ''
 for k in key:
  keyStr+=k
 print('the Key is:',keyStr)
 plainText = ''
 index = 0
 for ch in cipherText:
  c = chr((ord(ch)-ord(key[index%length]))%26+97)
  plainText += c
  index+=1
 return plainText # 返回明文

代码

这是解密部分的全部代码,注意需要自己添加密文文件的位置

def virginiaCrack(cipherText): # 解密函数
 length = getKeyLen(cipherText) #得到密钥长度
 key = getKey(cipherText,length) #找到密钥
 keyStr = ''
 for k in key:
  keyStr+=k
 print('the key:',keyStr)
 plainText = ''
 index = 0
 for ch in cipherText:
  c = chr((ord(ch)-ord(key[index%length]))%26+97)
  plainText += c
  index+=1
 return plainText
def openfile(fileName): # 读文件
 file = open(fileName,'r')
 text = file.read()
 file.close();
 text = text.replace('\n','')
 return text

def getKeyLen(cipherText): # 获取密钥长度
 keylength = 1
 maxCount = 0
 for step in range(3,18): # 循环密钥长度
  count = 0
  for i in range(step,len(cipherText)-step):
   if cipherText[i] == cipherText[i+step]:
     count += 1
  if count>maxCount:
   maxCount = count
   keylength = step
 return keylength

def getKey(text,length): # 获取密钥
 key = [] # 定义空白列表用来存密钥
 alphaRate =[0.08167,0.01492,0.02782,0.04253,0.12705,0.02228,0.02015,0.06094,0.06996,0.00153,0.00772,0.04025,0.02406,0.06749,0.07507,0.01929,0.0009,0.05987,0.06327,0.09056,0.02758,0.00978,0.02360,0.0015,0.01974,0.00074]
 matrix =textToList(text,length)
 for i in range(length):
  w = [row[i] for row in matrix] #获取每组密文
  li = countList(w) 
  powLi = [] #算乘积
  for j in range(26):
   Sum = 0.0
   for k in range(26):
    Sum += alphaRate[k]*li[k]
   powLi.append(Sum)
   li = li[1:]+li[:1]#循环移位
  Abs = 100
  ch = ''
  for j in range(len(powLi)):
    if abs(powLi[j] -0.065546)<Abs: # 找出最接近英文字母重合指数的项
     Abs = abs(powLi[j] -0.065546) # 保存最接近的距离,作为下次比较的基准
     ch = chr(j+97)
  key.append(ch)
 return key    

def countList(lis): # 统计字母频度
 li = []
 alphabet = [chr(i) for i in range(97,123)]
 for c in alphabet:
  count = 0
  for ch in lis:
   if ch == c:
    count+=1
  li.append(count/len(lis))
 return li

def textToList(text,length): # 根据密钥长度将密文分组
 textMatrix = []
 row = []
 index = 0
 for ch in text:
  row.append(ch)
  index += 1
  if index % length ==0:
   textMatrix.append(row)
   row = []
 return textMatrix

if __name__ == '__main__':
 cipherText = openfile(r'') # 这里要根据文档目录的不同而改变
 plainText= virginiaCrack(cipherText)
 print('the plainText:\n',plainText)

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持【听图阁-专注于Python设计】。

相关文章

使用rst2pdf实现将sphinx生成PDF

使用rst2pdf实现将sphinx生成PDF

当初项目文档是用sphinx写的,一套rst下来make html得到一整个漂亮的在线文档。现在想要将文档导出为离线的handbook pdf,于是找到了rst2pdf这个项目,作为sp...

Python中用PIL库批量给图片加上序号的教程

Python中用PIL库批量给图片加上序号的教程

女友让我给她论文的图片上加上字母序号,本来觉得是个很简单的事情,但那个白底黑字的圆圈序号却难住了我, 试了几个常用的软件,都不行。 后来用 PS + 动作,倒是能搞出来,不过也不容易,正...

python openvc 裁剪、剪切图片 提取图片的行和列

python openvc 裁剪、剪切图片 提取图片的行和列

python openvc 裁剪图片 下面是4个坐标代码: import cv2 #裁剪图片路径input_path,四个裁剪坐标为:y1,y2,x1,x2,保存剪裁后的图片路径ou...

python实现宿舍管理系统

python实现宿舍管理系统

Python综合应用——宿舍管理系统,供大家参考,具体内容如下/p> 通过对 python 的函数,变量的应用,编写简单的关系系统 实现功能: 1.新增学生 2.显示全部学生信息...

python实现最大子序和(分治+动态规划)

给定一个整数数组 nums ,找到一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和。 示例: 输入: [-2,1,-3,4,-1,2,1,-5,4], 输出:...