Python批量删除只保留最近几天table的代码实例
Python批量删除table,只保留最近几天的table
代码如下：
#!/usr/bin/python3
"""
批量删除table,只保留最近几天的table
"""
import pymysql
import re
def conn_(host='',usr='',passwd='',db='',port=3306,):
conn = pymysql.connect(host, usr, passwd, db, port,charset='utf8')
return conn
def del_table(conn_,table_pre='',table_suff='%Y%m%d',keep_count=3):
date_form = None
if table_suff == "%Y%m%d":
date_form = "_(\d{4}\d{1,2}\d{1,2})$"
date_len = 8
elif table_suff == "%Y-%m-%d":
date_form = "_(\d{4}-\d{1,2}-\d{1,2})$"
date_len = 10
elif table_suff == "%Y%m":
date_form = "_(\d{4}\d{1,2})$"
date_len = 6
elif table_suff == "%Y-%m":
date_form = "_(\d{4}-\d{1,2})$"
date_len = 7
else:
raise Exception("暂时不支持其他类型的时间后缀")
curs = conn_.cursor()
curs.execute('SHOW TABLES')
data = curs.fetchall()
table_ = r'%s'%table_pre+date_form
list_table = []
i = 0
for table in data:
mt = re.search(table_, table[0])
if mt:
if len(mt.groups()[0]) == date_len:
list_table.append((table[0], mt.groups()[0]))
i += 1
sorted(list_table, key=lambda date: date[1]) #按照表结构后缀时间升序排序
for j in range(i-keep_count):
sql = 'DROP TABLE if exists %s'%list_table[j][0]
curs.execute(sql)
curs.close()
conn_.close()
if __name__ == '__main__':
table_pre = "tree_product"
table_suff = "%Y%m%d"
# table_suff = "%Y-%m-%d"
# table_suff = "%Y%m"
# table_suff = "%Y-%m"
conn=conn_('10.0.0.11','root','sctele@root','sxf',port=3306)
del_table(conn,table_pre=table_pre,table_suff=table_suff,keep_count=1)
总结
以上就是这篇文章的全部内容了，希望本文的内容对大家的学习或者工作具有一定的参考学习价值，谢谢大家对【听图阁-专注于Python设计】的支持。如果你想了解更多相关内容请查看下面相关链接