python实现一个点绕另一个点旋转后的坐标

yipeiwu_com6年前Python基础

如下所示:

(x,y)为要转的点,(pointx,pointy)为中心点,如果顺时针角度为angle

srx = (x-pointx)*cos(angle) + (y-pointy)*sin(angle)+pointx

sry = (y-pointy)*cos(angle) - (x-pointx)*sin(angle)+pointy

(x,y)为要转的点,(pointx,pointy)为中心点,如果逆时针角度为angle

nrx = (x-pointx)*cos(angle) - (y-pointy)*sin(angle)+pointx

nry = (x-pointx)*sin(angle) + (y-pointy)*cos(angle)+pointy

import numpy as np
import math
import matplotlib.pyplot as plt
# 绕pointx,pointy逆时针旋转
def Nrotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 nRotatex = (valuex-pointx)*math.cos(angle) - (valuey-pointy)*math.sin(angle) + pointx
 nRotatey = (valuex-pointx)*math.sin(angle) + (valuey-pointy)*math.cos(angle) + pointy
 return nRotatex, nRotatey
# 绕pointx,pointy顺时针旋转
def Srotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 sRotatex = (valuex-pointx)*math.cos(angle) + (valuey-pointy)*math.sin(angle) + pointx
 sRotatey = (valuey-pointy)*math.cos(angle) - (valuex-pointx)*math.sin(angle) + pointy
 return sRotatex,sRotatey
pointx = 1
pointy = 1
sPointx ,sPointy = Nrotate(math.radians(45),pointx,pointy,0,0)
print(sPointx,sPointy)
plt.plot([0,pointx],[0,pointy])
plt.plot([0,sPointx],[0,sPointy])
plt.xlim(-3.,3.)
plt.ylim(-3.,3.)
plt.xticks(np.arange(-3.,3.,1))
plt.yticks(np.arange(-3.,3.,1))
plt.show()

import numpy as np
import math
import matplotlib.pyplot as plt
# 绕pointx,pointy逆时针旋转
def Nrotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 nRotatex = (valuex-pointx)*math.cos(angle) - (valuey-pointy)*math.sin(angle) + pointx
 nRotatey = (valuex-pointx)*math.sin(angle) + (valuey-pointy)*math.cos(angle) + pointy
 return nRotatex, nRotatey
# 绕pointx,pointy顺时针旋转
def Srotate(angle,valuex,valuey,pointx,pointy):
 valuex = np.array(valuex)
 valuey = np.array(valuey)
 sRotatex = (valuex-pointx)*math.cos(angle) + (valuey-pointy)*math.sin(angle) + pointx
 sRotatey = (valuey-pointy)*math.cos(angle) - (valuex-pointx)*math.sin(angle) + pointy
 return sRotatex,sRotatey
 
x1 = np.array([1,2,3])
y1 = np.array([1,2,3])
x2 = np.array([3,6])
y2 = np.array([2,1])
# x2往x1上拼
disx = x2[0]-x1[0]
disy = y2[0]-y1[0]
removeX2 = x2-disx
removeY2 = y2-disy
tany1 = y1[-1]-y1[0]
tanx1 = x1[-1]-x1[0]
angle1 = math.degrees(np.arctan(tany1/tanx1))
tany2 = y2[-1]-y2[0]
tanx2 = x2[-1]-x2[0]
angle2 = math.degrees(np.arctan(tany2/tanx2))
disAngle = angle2-angle1
print(angle1)
print(angle2)
print(disAngle)
if disAngle<0:
 rotateX,rotateY = Nrotate(math.radians(abs(disAngle)),removeX2,removeY2,x1[0],y1[0])
else:
 rotateX,rotateY = Srotate(math.radians(abs(disAngle)),removeX2,removeY2,x1[0],y1[0])
plt.plot(x1,y1,color='red')
plt.plot(removeX2,removeY2,color='green')
plt.scatter(rotateX,rotateY,color='yellow')
plt.xlim(0.,10.)
plt.ylim(0.,10.)
plt.xticks(np.arange(0.,10.,1))
plt.yticks(np.arange(0.,10.,1))
plt.show()

以上这篇python实现一个点绕另一个点旋转后的坐标就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持【听图阁-专注于Python设计】。

相关文章

python计算列表内各元素的个数实例

如下所示: list = [1,2,3,4,5,6,7,5,4,3,2,12] set = set(list) dict = {} for item in set: dict.u...

python 3.3 下载固定链接文件并保存的方法

python 3.3 下载固定链接文件并保存。 import urllib.request print ("downloading with urllib") url = '/zb_...

Python运行不显示DOS窗口的解决方法

方法1:pythonw xxx.py 方法2:将.py改成.pyw (这个其实就是使用脚本解析程序pythonw.exe) 跟 python.exe 比较起来,pythonw.exe 有...

使用python+whoosh实现全文检索

whoosh的官方介绍:http://whoosh.readthedocs.io/en/latest/quickstart.html 因为做的是中文的全文检索需要导入jieba工具包以及...

python实现beta分布概率密度函数的方法

python实现beta分布概率密度函数的方法

如下所示: beta分布的最大特点是其多样性, 从下图可以看出, beta分布具有各种形态, 有U形, 类似正态分布的形状, 类似uniform分布的形状等, 正式这一特质使beta...